CSE Logic Mock Quiz

CSE Logic Mock Quiz Answer Keys

Here are the answers to our Civil Service Exam Logic mock quiz.

1. e. Emily
    Explanation: 
                           1. Anna > Betty
                           2. Dana > Betty
                           3. Dana > Cindy
                           4. Betty > Emily
                           5. Cindy > Emily

From the information given, Emily is shorter than both Betty and Cindy, making Emily the shortest among the group.

 

2. d. Sam
    Explanation: 
                           1. Tom and Tim > Jerry
                           2. Sam > Tim and Tom
                           3. Tim and Tom > Jerry
                           4. Jerry > Bob
                           5. Tim and Tom> Bob

From the information given:

• • Tom is faster than Jerry.
  • Sam is faster than Tim.
  • Tim is faster than Jerry.
  • Jerry and Tim are faster than Bob.
  • Tom is as fast as Tim.

Since Sam is faster than Tim, and Tim is faster than Jerry (who is faster than Bob), the hierarchy is: Sam > Tim and Tom > Jerry > Bob. Tom who is as fast as Tim, is faster than Jerry. Therefore, Sam is the fastest.

 

3. a. Eva
    Explanation: 
                           1. Alex arrives before Bob.
                           2. David arrives before Bob.
                           3. Cindy arrives after David.
                           4. Bob arrives before Eva.
                           5. Cindy arrives before Eva.

The order of arrivals is:

1. 1. Alex
   2. David
   3. Bob
   4. Cindy
   5. Eva

Therefore, Eva arrives last.

 

4. c. Mouse
    Explanation: 
                           1. Dog is called cat.
                           2. Cat is called mouse.
                           3. Mouse is called bird.
                           4. Bird is called fish.
                           5. Fish is called lion.
                           6. Lion is called tiger.
                           7. Tiger is called dog. 

The animal that meows is a cat. According to the given terms, cat is called mouse. Therefore, the animal that meows is called mouse.

 

5. c. Cherry
    Explanation: 
                           1. Apple is called banana.
                           2. Banana is called cherry.
                           3. Cherry is called date.
                           4. Date is called elderberry.
                           5. Elderberry is called fig.
                           6. Fig is called grape.
                           7. Grape is called apple.

The fruit that is yellow and curved is a banana. According to the given terms, banana is called cherry. Therefore, the fruit that is yellow and curved is called cherry.

 

6. d. Summer
    Explanation: 
                           1. Winter is called spring.
                           2. Spring is called summer.
                           3. Summer is called fall.
                           4. Fall is called monsoon.
                           5. Monsoon is called dry.
                           6. Dry is called winter.

Flowers typically bloom in spring. According to the given terms, spring is called summer. Therefore, the season in which flowers typically bloom is called summer.

 

7. d. Sonata-allegro
    Explanation: 
          Sonata, Symphony, Concerto, and Opera are all types of musical compositions or performances. Sonata-allegro, however, refers specifically to a musical form or structure often used in the first movement of sonatas, symphonies, and concertos. Therefore, Sonata-allegro does not belong with the others, which are broader categories of musical works.

 

8. b. Anvil
    Explanation: 
        Hammer, Wrench, Chisel, and Screwdriver are all hand tools used directly by a person to perform tasks such as striking, turning, carving, or driving screws. Anvil, however, is not a hand tool but rather a heavy iron block on which metal can be hammered and shaped. Therefore, Anvil does not belong with the others.

 

9. a. Lithium
    Explanation: 
      Neon, Helium, Argon, and Krypton are all noble gases, which are elements in Group 18 of the periodic table characterized by their lack of reactivity due to having full valence electron shells. Lithium, however, is an alkali metal found in Group 1 of the periodic table, which is highly reactive and not a noble gas. Therefore, Lithium does not belong with the others.

 

10. b. Alise, Alicia, Alice, Alyce
      Explanation: 
      1. Alice is between Alicia and Alise.
      2. Alicia is between Alyce and Alice.
      3. Alyce is not the first in line.

     From this information:

• Since Alice is between Alicia and Alise, Alicia and Alise must be on either side of Alice.
• Alicia is also between Alyce and Alice, so Alyce must be on one side of Alicia, with Alice still between Alicia and Alise.
• Alyce cannot be first, which means Alise must be first.

     The arrangement that satisfies all conditions is:
           b. Alise, Alicia, Alice, Alyce.

 

11. c. Green
      Explanation:

• • The Blue car is between the Red car and the Green car.
  • The Yellow car is between the Green car and the Black car.
  • The Red car is not last in line.

       From this information:

• • Blue being between Red and Green means the order could be Red, Blue, Green or Green, Blue, Red.
  • Yellow being between Green and Black means the order could be Green, Yellow, Black or Black, Yellow, Green.
  • Since Red is not last, it cannot be the last car.

The arrangement that satisfies all conditions is:
Red, Blue, Green, Yellow, Black.

 

12. a. Cheetah
      Explanation:

• • The Rabbit finishes before the Cheetah but after the Horse.
  • The Horse finishes after the Turtle.
  • The Dog finishes after the Cheetah.

Using the information provided, we can deduce the following:

1. 1. 1. Rabbit (R) finishes before Cheetah (C) but after Horse (H):

         • This gives us H > R > C.

      2. Horse (H) finishes after Turtle (T):

         • This gives us T > H.

      3. Dog (D) finishes after Cheetah (C):

         • This gives us C > D.

Combining all constraints:

• • • T > H > R > C > D

Therefore, the order of finishing is:

• • • 1st: Turtle
    • 2nd: Horse
    • 3rd: Rabbit
    • 4th: Cheetah
    • 5th: Dog

 

13. a. 15 minutes
      Explanation:

To solve the problem of getting all four people across the bridge in the shortest time, we need to carefully plan each crossing so that we minimize the total time taken. Let’s analyze the situation:

1. 1. Understand the crossing times:

      • Person A: 1 minute
      • Person B: 2 minutes
      • Person C: 5 minutes
      • Person D: 8 minutes

   2. Constraints:

      • Only two people can cross the bridge at a time.
      • They have one torch, and someone must bring the torch back each time.
      • The crossing time for two people is determined by the slower person.

We want to find the optimal sequence of crossings. A good strategy is to minimize the time taken for the slower people to cross by pairing them with the faster ones efficiently.

Optimal Strategy

Here’s a step-by-step optimal crossing strategy:

1. 1. First crossing: A and B cross the bridge. Time taken = 2 minutes (since B is slower).
   2. Return trip: A returns with the torch. Time taken = 1 minute.
   3. Second crossing: C and D cross the bridge. Time taken = 8 minutes (since D is slower).
   4. Return trip: B returns with the torch. Time taken = 2 minutes.
   5. Final crossing: A and B cross the bridge again. Time taken = 2 minutes.

Let’s add up the times:

1. 1. A and B cross: 2 minutes
   2. A returns: 1 minute
   3. C and D cross: 8 minutes
   4. B returns: 2 minutes
   5. A and B cross: 2 minutes

Total time = 2 + 1 + 8 + 2 + 2 = 15 minutes

Therefore, the shortest time for all four people to cross the bridge is 15 minutes.

 

14. c. 25 minutes
      Explanation:

We need to plan each crossing so that the total time is minimized. Let’s analyze the crossing times and develop an optimal strategy.

1. • First crossing: E and F cross the river. Time taken = 4 minutes (since F is slower).
   • Return trip: E returns with the lantern. Time taken = 3 minutes.
   • Second crossing: G and H cross the river. Time taken = 10 minutes (since H is slower).
   • Return trip: F returns with the lantern. Time taken = 4 minutes.
   • Final crossing: E and F cross the river again. Time taken = 4 minutes.

Let’s add up the times:

1. • E and F cross: 4 minutes
   • E returns: 3 minutes
   • G and H cross: 10 minutes
   • F returns: 4 minutes
   • E and F cross: 4 minutes

Total time = 4 + 3 + 10 + 4 + 4 = 25 minutes

Therefore, the shortest time for all four buffalos to cross the river is 25 minutes.

 

15. a. 19 minutes
      Explanation:

We need to plan the crossings to minimize the total time. Here’s an optimal strategy:

1. • First crossing: Student A and Student B cross the road. Time taken = 3 minutes (since B is slower).
   • Return trip: Student A returns with the flashlight. Time taken = 1 minute.
   • Second crossing: Student C and the teacher cross the road. Time taken = 9 minutes (since the teacher is slower).
   • Return trip: Student B returns with the flashlight. Time taken = 3 minutes.
   • Final crossing: Student A and Student B cross the road again. Time taken = 3 minutes.

Let’s add up the times:

1. • Student A and Student B cross: 3 minutes
   • Student A returns: 1 minute
   • Student C and the teacher cross: 9 minutes
   • Student B returns: 3 minutes
   • Student A and Student B cross: 3 minutes

Total time = 3 + 1 + 9 + 3 + 3 = 19 minutes

Therefore, the shortest time for the teacher and all three students to cross the road is 19 minutes.

This CSE Logic Mock Quiz is quite tough so getting at least 11 correct answers is great. Don’t forget to check out more FREE CSE LOGICAL REASONING REVIEWERS via this link. <–